\int (\frac{1}{x^2}+\frac{ \sin ^3 x+\cos ^3 x}{ \sin ^2 x \cos ^2 x}) \dx=

Correct Answer is : (sinx−cosx)x−sinxcosxxsinxcosx+C

\frac{( \sin x-\cos x) x- \sin x \cos x}{x \sin x \cos x}+C

-\frac{1}{x}+\frac{ \sin x+\cos x}{\cos x- \sin x}+c

-\frac{1}{x}+\frac{ \sin x-\cos x}{ \sin ^2 x \cos ^2 x}+C

\frac{( \sin x-\cos x) x- \sin x-\cos x}{x( \sin x+\cos x)}+C

TG EAMCET 2 May 2025 Shift 2 Paper

Question : 72 of 160

Marks: +1, -0

∫(‌

+‌

sin‌3x+cos3x

sin‌2xcos2x

)‌dx=

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