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Question : 64 of 160
Marks:
+1,
-0
Solution:
Given,
‌‌(tan−1(‌))=‌(tan−1x)‌‌ By LHS, ‌‌(tan−1(‌))‌=‌‌(‌)‌=‌[‌| (1−x)(1)−(1+x)(−1) |
| (1−x)2 |
]‌=‌[‌]=‌And by RHS,
‌(tan−1x)=‌∴ Assertion is true.
For reason ( R )
when
x<1, let
x=tan‌θ⇒θ=tan−1x∴‌tan−1(‌)=tan−1(‌)‌=tan−1(tan(‌+θ))=‌+θ‌=‌+tan−1xWhen
x>1, then
tan−1x>1∴‌‌‌<0so,
tan−1(‌) lies in
(−‌,0)∴tan−1(‌)=‌+tan−1x∴ Reason is also true.
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