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Question : 38 of 160
Marks:
+1,
-0
Solution:
Given,
P(A)=‌,P(B)=‌,
P(A∩B)‌=‌∴‌‌P(‌)‌=‌=‌=‌P(‌)‌=‌‌=‌Now,
P(A∪B)=P(A)+P(B)−P(A∩B)‌=‌+‌−‌‌=‌=‌‌∴P((A∪B)′=1−‌=‌.And
P(B′)=‌‌∴P(‌)=‌=‌×‌=‌‌∴P(‌)+P(‌)=‌+‌=‌
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