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Question : 28 of 160
Marks:
+1,
-0
Solution:
We have,
r1=4,r2=8 and
r3=24 ∴‌4=‌∆∕s−a,8=‌∆∕s−b‌ and ‌24=‌∆∕s−c ⇒s−a=‌∆∕4...(i) s−b=‌...(ii) ‌ And ‌‌‌s−c=‌‌‌...(iii) On adding these three equations, we get
‌3s−(a+b+c)=‌+‌+‌ ⇒3s−2s=‌=‌⇒s=‌∆ From Eq. (i),
a=s−‌=‌−‌=‌=‌ From Eq. (ii),
b=s−‌=‌∆−‌=‌∆ From Eq. (iii),
c=s−‌=‌∆−‌=‌∆ ∴a:b:c=‌:‌∆:‌∆=4:7:9
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