TG EAMCET 2 May 2025 Shift 2 Paper

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Question : 2 of 160

Marks: +1, -0

The inverse of the function y=‌

10x−10−x

10x+10−x

+1 is x=

log(‌
y
2−y
)
log10(‌
y
2−y
)
‌
1
10
‌log(‌
y
1−y
)
‌
1
2
log10(‌
y
2−y
)

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