TG EAMCET 2 May 2025 Shift 2 Paper

Let the number of B atom in ccp=N
Number of octahedral voids =N
Number of tetrahedral voids =2N
Number of A atoms from octahedrals voids =‌

N

2

Number of A atoms from tetrahedral voids =‌

1

2

×2N=N
Total number of A atoms =‌

N

2

+N=‌

3N

2

Ratio of A:B=‌

3N

2

:N or 3:2
Thus molecular formula A3B2.