\int e^{4 x}( \sin 3 x-\cos 3 x) \dx=

Correct Answer is : e4x25(sin3x−7cos3x)+C

\frac{e^{4 x}}{25}(7 \sin 3 x-\cos 3 x)+C

\frac{e^{4 x}}{25}( \sin 3 x-7 \cos 3 x)+C

\frac{e^{4 x}}{5}(7 \sin 3 x+\cos 3 x)+C

\frac{e^{4 x}}{5}( \sin 3 x+7 \cos 3 x)+C

TG EAMCET 2 May 2025 Shift 1 Paper

Question : 73 of 160

Marks: +1, -0

∫e4x(sin‌3x−cos‌3‌x)‌dx=

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