If x=\frac{t^2}{1+t^5}, y=\frac{2 t^3}{1+t^5} and t \neq-1 is a perimeter, then \frac{d y}{d x}=

Correct Answer is : 2t(3−2t5)(2−3t5)

\frac{2 (3+2 t^5) }{ (2-3 t^5) }

\frac{2 t (3-2 t^5) }{ (2-3 t^5) }

\frac{2 t (3-2 t^5) }{ (2+3 t^5) }

\frac{2 (3+2 t^5) }{ (2+3 t^5) }

TG EAMCET 2 May 2025 Shift 1 Paper

Question : 66 of 160

Marks: +1, -0

If x=‌

1+t5

,y=‌

2t3

1+t5

and t≠−1 is a perimeter, then ‌

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