| ‌=1(4×13−(−6)×(−11))−(−3)(−2×13−(−6)×7)−5(−2×(−11)−7×4) ‌=1(52−66)+3(−26+42)−5(22−28) ‌=−14+48+30=64 Since, |adj‌A|=|A|n−1, for n×n matrix A So, for 3×3 matrix, |adj‌A|‌=|A|3−1=|A|2 ∴‌‌∴‌‌|adj‌A|‌=|A|2=(64)2=4096 √|adj‌A|‌=√4096=64