TG EAMCET 2 May 2025 Shift 1 Paper

Let the centroid be G(x,y). The coordinates of the centroid of triangles with vertices (x1,y1),(x2,y2) and (x3,y3) are x=‌

x1+x2+x3

3

and y=‌

y1+y2+y3

3

Substituting the coordinates of A,B and P.
x=‌‌

2+3+t

3

=‌

5+t

3

y=‌‌

3+2+t2

3

=‌

5+t2

3

⇒3x−5=t,y=‌

5+(3x−5)2

3

‌(∵t=2x−5)
⇒3y=5+9x2+25−30x
⇒9x2−30x−3y+30=0
⇒3x2−10x−y+10=0
The equation of the locus of the centroid of △ABC is 3x2−10x−y+10=0