TG EAMCET 2 May 2025 Shift 1 Paper

Total Alphabets are A, D, E, H, L, N Letters before H are A, D, E.
So, the number of letters before H=3×5 !
=3×120=360
Letters before E are A, D.
So, the number of letters before E=2×4 !
=2×24=48
Letters before L are A,D.
So, the number of letters before L
=2×3!=12
Letters before N is D
So, the number of letters with N only
⇒‌‌1×1!=1
So, total words =360+48+12+1=421
Now, only 1 letter remaining, that is D .
So, Rank of HELAND =421+1=422