TG EAMCET 2 May 2025 Shift 1 Paper

Freundlich adsorption isotherm equation:
‌

x

m

=kp1∕n
where
‌

x

m

=‌ mass of gas adsorbed per unit mass of adsorbent, ‌
p= equilibrium pressure,
k and n= empirical constants,
n>1.
Or, taking logarithms,
log‌

x

m

=log‌k+‌

1

n

‌log‌p
Option A:
‌

x

m

=kp1∕n‌‌(n>1)
Correct.
Option B:
Extent of adsorption of gas is more at high temperature than at low temperature.
Adsorption is an exothermic process.
Hence, increasing temperature decreases adsorption (Le Chatelier's principle).
Incorrect statement.
Option C:
‌

1

n

represents the slope of the isotherm (in log-log plot)
Since log‌

x

m

=log‌k+‌

1

n

‌log‌p,
Correct.
Option D:
log‌

x

m

=log‌k+‌

1

n

‌log‌p holds good over a limited range of pressures.
At very high or very low pressures, Freundlich isotherm deviates.
Correct.
Final Answer:
Option B - Extent of adsorption of gas is more at high temperature than at low temperature - is not correct about Freundlich adsorption isotherm.