Symbiosis National Aptitude Test SNAP 2019 Paper

Let ABCD is a 16 × 30 ${\mathit{m}}^2$ rectangular field and a robot of length 4 m is placed at corner A facing towards the diagonally opposite corner C.

Now AC = $\sqrt{{\left(\mathit{A}\mathit{B}\right)}^2+{\left(\mathit{B}\mathit{C}\right)}^2}$
= $\sqrt{{\left(30\right)}^2+{\left(16\right)}^2}$
= 34 m
Length to be covered by robot in 15 sec
= 34 – 4 = 30 m
Speed of the robot = $\frac{30}{15}$ = 2 m/s.