Symbiosis National Aptitude Test SNAP 2019 Paper

Question : 50 of 110

Marks: +1, -0

In the given diagram, ∠CAB = 60° and BC = a, AC = b and AB = c

Then which of the following connect?

Solution:

From cosine formula
cos (ϑBAC) =

{AB^2+AC^2-BC^2}/{2.AB.AC}

cos (60°) =

{c^2+b^2-a^2}/{2.b.c}

1/2

{b^2+c^2-a^2}/{2bc}

a^2

b^2 + c^2

– bc

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