Symbiosis National Aptitude Test SNAP 2015 Paper

For simple Interest
60% increase in amount so, that
⇒ SI = $\frac{\mathit{P}\mathit{R}\mathit{T}}{100}$
⇒ $\frac{60\mathit{P}}{100}$ = $\frac{\mathit{P}\times \mathit{R}\times 6}{100}$
R = 10%
Now, for compound interest
A = $\mathit{P}{\left(1+\frac{\mathit{r}}{100}\right)}^{\mathit{t}}$
= $12000{\left(1+\frac{10}{100}\right)}^3$
= $12000\times \frac{1331}{1000}$
= 12 × 1331 = 15972
Compound Interest = 15972 – 12000
= ₹ 3972