Symbiosis National Aptitude Test SNAP 2013 Paper

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Question : 29 of 150

Marks: +1, -0

In the triangle ABC, MN is parallel to AB. Area of trapezium ABNM is twice the area of triangle CMN. What is ratio of CM : AM ?

$1/{√3+1}$
${√3-1}/2$
${√3+1}/2$
None of these

Solution:

{ar(ΔCMN)}/{ar(ABNM)}

=

1/2

∴

{ar(ΔCMN)}/{ar(ΔCAB)}

=

1/3

⇒

{MN}/{AB}

=

{CM}/{CA}

=

1/√3

⇒

{CM}/{MA}

=

1/{√3-1}

=

{√3+1}/2

MA = (CA – CM)

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