Symbiosis National Aptitude Test SNAP 2013 Paper

Let the speed of train = ${\mathit{v}}_1$ km/h
and speed of taxi = ${\mathit{v}}_2$ km/h
$\frac{300}{{\mathit{v}}_1}+\frac{200}{{\mathit{v}}_2}$ = $\frac{11}{2}$
⇒ $\frac{3}{{\mathit{v}}_1}+\frac{2}{{\mathit{v}}_2}$ = $\frac{11}{200}$ ... (i)
$\frac{260}{{\mathit{v}}_1}+\frac{240}{{\mathit{v}}_2}$ = $\frac{336}{60}$
⇒ $\frac{26}{{\mathit{v}}_1}+\frac{24}{{\mathit{v}}_2}$ = $\frac{336}{600}$ ,,, (ii)
From eqs. (i) and (ii)
$\frac{36}{{\mathit{v}}_1}+\frac{24}{{\mathit{v}}_2}$ = $\frac{11\times 12}{200}$
$\frac{36}{{\mathit{v}}_1}+\frac{24}{{\mathit{v}}_2}$ = $\frac{336}{600}$
⇒ $\frac{10}{{\mathit{v}}_1}$ = $\frac{132}{200}-\frac{336}{600}$
= $\frac{396-336}{600}$
= $\frac{1}{10}$
${\mathit{v}}_1$ = 100 km/h