SSE JE Electrical Engineering 29 Oct 2020 Shift 2 Papers

Question : 152 of 200

Marks: +1, -0

The impedance of a circuit placed across a 120 V, 50 Hz source is (10 + j20) Ω. Find the current through the load.

Solution:

The given system is represented as follows:

Current in the circuit

= \text "voltage "/\text " Load impedance"

Current

={120}/{10+ j 20}

={120}/{10+ j 20} ×{(10- j 20)}/{(10- j 20)}

={(1200- j 2400)}/{100+400}

={12}/{5}-{24 j }/{5}

Current = 2.4 – j 4.8 A

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