SSE JE Electrical Engineering 29 Oct 2020 Shift 2 Papers

From the given daily load curve, the load distribution is as follows:
(0 – 6) hours – 40 MW for 6 hours
(6 to 10) hours – 50 MW for 4 hours
(10 to 12) hours – 60 MW for 2 hours
(12 to 16) hours – 50 MW for 4 hours
(16 to 20) hours – 70 MW for 4 hours
(20 to 24) hours – 40 MW for 4 hours
Total load = (40 × 6) + (50 × 4) + (60 × 2) + (50 × 4) + (70 × 4) + (40 × 4) = 1200 MW
Total number hours = 24
Average load = $\frac{1200}{24}$ = 50 MW