SSE JE Electrical Engineering 29 Oct 2020 Shift 2 Papers

Question : 118 of 200

Marks: +1, -0

Find the current

i_1

and voltage

v_2

in the given network.

$i_1 = 1.5 \A, v_2 = -18\V$
$i_1 = 1.5 \A, v_2= 46\V$
$i_1 = 5.5 \A, v_2= 18\V$
$i_1 = -1.5 \A, v_2= 46\V$

Validate

Solution:

● 32 V and 14 V Voltage source equivalent to 46 V because both voltage source is in series.
● 2 A and 3.5 A Current source equivalent to 1.5 A in downwards direction because both are in anti-parallel to each other.
Hence circuit becomes:

From the above-simplified circuit diagram:
40 Ω resistance is connected in parallel with the 46 V voltage source.

∴ V_2 = 46 \V

And,

i_1 = 1.5 \A

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