SSE JE Electrical Engineering 28 Oct 2020 Shift 1 Papers

Question : 197 of 200

Marks: +1, -0

Find the value of

\G_\eq

in the following circuit.

Solution:

S _{1}=6 S , S _{2}=5 S , S _{3}=20 S

So,

R _{1}={1}/{ S _{1}}={1}/{6} \ω

R _{2}={1}/{ S _{2}}={1}/{5} \ω

R _{3}={1}/{ S _{3}}={1}/{20} \ω

R _{23}= R _{2}+ R _{3}={1}/{5}+{1}/{20}

={5}/{20}={1}/{4} \ω

R _{ eq }={ R _{1} ×R _{23}}/{ R _{1}+ R _{23}}

={{1}/{6} ×{1}/{4}}/{{1}/{6}+{1}/{4}}

={{1}/{24}}/{{10}/{24}}

={1}/{24} ×{24}/{10}

={1}/{10} \ω

S _{ eq }={1}/{ R _{ eq }}=10 S

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