SSE JE Electrical Engineering 28 Oct 2020 Shift 1 Papers

Question : 168 of 200

Marks: +1, -0

The 3-ϕ, Y - load of impedances each (6 + j9) is supplied through a line having an impedance of (1 + j2) Ω. The supply voltage is 400 volts 50 Hz. Determine the line current.

17.7 A
27.7 A
47.7 A
37.7 A

Validate

Solution:

Load impedance = 6 + j9
Line impedance = 1 + j2
Total impedance = 7 + j11
Magnitude of total impedance = 13.038 Ω
Supply voltage

(\V_\S)

= 400 V
Line current

=400/{√3 ×13.038} =17.7\A

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