SSE JE Electrical Engineering 28 Oct 2020 Shift 1 Papers

1.When 20 V Source Is Acting Alone Applying KCL
$\frac{{\mathrm{V}}_{\mathrm{x}}-20}{20}+\frac{{\mathrm{V}}_{\mathrm{x}}}{4}=0.1{\mathrm{V}}_{\mathrm{x}}$
${\mathrm{V}}_{\mathrm{x}}\left(0.05+0.25-0.1\right)=1$
${\mathrm{V}}_{\mathrm{x}}=5\mathrm{V}$
2.When 4 A Source Is Acting Alone Applying KCL,
$0.1{\mathrm{V}}_{\mathrm{x}}+4=\frac{{\mathrm{V}}_{\mathrm{x}}}{4}+\frac{{\mathrm{V}}_{\mathrm{x}}}{20}$
${\mathrm{V}}_{\mathrm{x}}=20\mathrm{V}$
Total response when both sources acting is the sum of responses when individual sources acting alone
${\mathrm{V}}_{\mathrm{x}}={\mathrm{V}}_{\mathrm{x}1}+{\mathrm{V}}_{\mathrm{x}2}$ $=5+20=25\mathrm{V}$