SSE JE Electrical Engineering 24 March 2021 Shift 2 Paper

Question : 193 of 200

Marks: +1, -0

A 230-V, single-phase domestic energy meter has a constant load of 4 A passing through it for 6 h at unity power factor. The meter disc makes 2208 revolutions during this period. What will be the energy consumed by the load if the meter disc completes 1240 revolutions?

2.5 kWh
2.8 kWh
3.5 kWh
3.1 kWh

Validate

Solution:

Given that,
Voltage = 230 V
Current = 4 A
cos ϕ = 1
Energy consumed in 6 hours is given as,

\E_1 = 230 × 4 × 6 × 1

= 5520 \Wh

\R_1 = 2208

From above concept,

\R∝\E

∴\R _{1} \E _{2}= \R _{2} \E _{1}

Given,

\R _{2}=1240

Hence,

\E _{2}={ \R _{2} \E _{1}}/{ \R _{1}}

={1240 ×5520}/{2208}=3100 \Wh

Hence, the Energy consumed in 1240 revolution is 3.1 kWh.

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