SSE JE Electrical Engineering 24 March 2021 Shift 2 Paper

Question : 189 of 200

Marks: +1, -0

In a 3-phase system, two-wattmeter method is used to measure the power. If one of the wattmeters shows a negative reading and the other shows a positive reading, and the magnitude of the readings are not the same, then what will be the power factor (p.f.) of the load?

0.0 < p.f. < 0.5
0.5 < p.f. < 1.0
1
0.5

Validate

Solution:

\W_1 = -\ve, \W_2 = +\ve

|\W_1| ≠ |\W_2|,

then the power factor range is given as
The range of ϕ is, 60 < ϕ < 90
Now the range of power factor is, 0.5 > cos ϕ > 0.

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