SSE JE Electrical Engineering 24 March 2021 Shift 2 Paper

Question : 186 of 200

Marks: +1, -0

Find the voltage

\V_0

across 4 Ω resistor in the following circuit.

Solution:

Apply KCL at node 'a'

i _{0}=0.5 i _{0}+3

0.5 i _{0}=3

i _{0}=6 \A

∴v _{0}=4 i _{0}=4 ×6= 2 4 \V

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