SSE JE Electrical Engineering 24 March 2021 Shift 2 Paper

Question : 165 of 200

Marks: +1, -0

Find the current required by a 400 V, 10 H.P. DC motor at 73.55% efficiency.

Solution:

\P _{ \m }=10 \HP

=10 × 746=7460 \W

\V =400

\η=0.7355

\η=7460 /(400 ×\I )

⇒0.7355=7460 /(400 ×\I )

⇒\I =25.35 ≈ 2 5 \A

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