SSE JE Electrical Engineering 24 March 2021 Shift 2 Paper

Question : 160 of 200

Marks: +1, -0

A steam power station has an overall efficiency of 25%, and 0.5 kg of coal is burnt per kWh of electrical energy generated. Determine the calorific value of fuel.
(Take heat equivalent of 1 kWh as 860 kcal)

1720 kcal/kg
6880 kcal/kg
3400 kcal/kg
4650 kcal/kg

Validate

Solution:

Overall efficiency = 25 % , 0.5 kg coal burnt.
Let x cal /kg be the calorific value of the fuel.
Heat equivalent of 1 kWh = 860 kcal

\η_{{\overall }}={ \EO }/{ \HC }

0.25={860}/{0.5 x }

x ={860000}/{25 ×5}

x =6880 \kcal \/ \kg

Go to Question:

Prev Question

Next Question