SSE JE Electrical Engineering 24 March 2021 Shift 2 Paper

Question : 150 of 200

Marks: +1, -0

The maximum values of the alternating voltage and current are 400 V and 20 A, respectively, in a circuit. The frequency of the alternating quantities is 50 Hz, and these quantities are sinusoidal. The phase angle of the current with respect to voltage is θ. Choose the correct expression for the voltage and current with respect to time t

$v(t)=400 \sin (100 \πt) \V$ , $i(t)=20 \sin (100 \πt) \A$
$v ( t )=400 \sin (100 \πt ) \V$ , $i ( t )=20 \sin (100 \πt +\θ) \A$
$v ( t )={400}{√{2}} \sin (100 \π t ) \V$ , $i ( t )={20}/{√{2}} \sin ((100+\θ\π) t ) \A$
$v ( t )={400}/{√{2}} \sin (100 \π t ) \V$ , $i ( t )={20}/{√{2}} \sin (100 \πt ) \A$

Validate

Solution:

\V _{ \m }=400 \V , \I _{ \m }=20 \A , \f =50 \HZ

\ω=2 \π\f =2 \π×50=100 \π

By substituting the values in general representation

\V =400 \sin 100 \πt

\I =20 \sin (100 \πt +\θ)

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