SSE JE Electrical Engineering 24 March 2021 Shift 2 Paper

Question : 127 of 200

Marks: +1, -0

A transistor connected in a common base configuration has the following readings

\I_\E = 2 \mA

and

\I_\B = 20 \μ\A

. Find the current gain α.

Solution:

\I _{ \E }=2 \mA

\I _{ \B }= \I _{ \B }=20 \µ\A =0.02 \mA

From above concept,

\I _{ \C }=2 \mA -0.02 \mA =1.98 \mA

Current amplification factor is given as,

\α={ \I _{ \C }}/{ \I _{ \B }}={1.98}/{2}=0.99

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