SSE JE Electrical Engineering 24 March 2021 Shift 2 Paper

Question : 125 of 200

Marks: +1, -0

In an element from t = 0 s to t = 5 s, 12 C of charge is entered. Find the flow of current in that element.

Solution:

dq = Δq = change in flow of charge = 12 C
dt = Δt = change in time = 5 - 0 = 5 sec

{\Current}( \I )={ \dq }/{ \dt }

={\Δ\q }/{\Δ\t } = 12/5 = 2.4\A

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