SSE JE Electrical Engineering 24 March 2021 Shift 1 Paper

Question : 186 of 200

Marks: +1, -0

The impedance of a circuit placed across a 120 V, 50 Hz source is (10 + j20) Ω. Find the current through the load.

Solution:

The given system is represented as follows:

Current in the circuit

= \text "voltage "/ \text "Load impedance"

Current

={120}/{10+ j 20}

={120}/{10+ j 20} × {(10- j 20)}/{(10- j 20)}

={(1200- j 2400)}/{100+400}

={12}/{5}-{24 j }/{5}

Current

= 2.4 - j 4.8 \A

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