SSE JE Electrical Engineering 24 March 2021 Shift 1 Paper

Question : 161 of 200

Marks: +1, -0

The total current flowing through a parallel connection of 20 Ω and 60 Ω resistors is 40 A. What will be the current flowing through the 60 Ω resistor?

15 A
20 A
30 A
10 A

Validate

Solution:

Let

\R _{1}=20 \Ω, \R _{2}=60 \Ω, \I =40 \A

\I _{ \R 2}= \I ({ \R _{1}}/{ \R _{1}+ \R _{2}})

\I _{ \R 2}= \I _{60 \Ω}=40 ×(20 / 80)

\I _{60 \Ω}= 1 0 \A

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