SSE JE Electrical Engineering 24 March 2021 Shift 1 Paper

Question : 158 of 200

Marks: +1, -0

A resistance is rated for 2.5 kΩ, 1 watt. Determine its maximum voltage and current ratings.

Solution:

R =2.5 \k \Ω, \P =1\Watt

From equation (i)

1= \I ^{2} ×2500={ \V ^{2}}/{2500}

\I ={1}/{√{2500}}=20 \mA

\V =√{2500}=50 \V

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