SSE JE Electrical Engineering 24 March 2021 Shift 1 Paper

6 Ω and 3 Ω resistors are in parallel, equivalent resistance $=\frac{6\times 3}{6+3}=2\mathrm{\Omega }$
1 Ω and 5 Ω resistors are in series, equivalent resistance = 1 + 5 = 6 Ω
2 Ω and 2 Ω resistors are in series, equivalent resistance = 2 + 2 = 4 Ω6 Ω and 4 Ω resistors are in parallel, equivalent resistance $=\frac{6\times 4}{6+4}=2.4\mathrm{\Omega }$ 4 Ω, 2.4 Ω and 8 Ω resistors are in series.
Equivalent resistance $\left({\mathrm{R}}_{\mathrm{eq}}\right)$ = 4 + 2.4 + 8 = 14.4 Ω