SSE JE Electrical Engineering 24 March 2021 Shift 1 Paper

Two terminals of Op-Amp i.e.; Inverting Terminal and Non-Inverting Terminal are at equipotential.
Apply KCL at node $1{\mathrm{V}}_{\mathrm{pp}}$,
$\frac{1{\mathrm{V}}_{\mathrm{pp}}-0}{10\mathrm{k}}+\frac{1{\mathrm{V}}_{\mathrm{pp}}-{\mathrm{V}}_0}{100\mathrm{k}}=0$
$\frac{10{\mathrm{V}}_{\mathrm{pp}}+1{\mathrm{V}}_{\mathrm{pp}}-{\mathrm{V}}_0}{100\mathrm{K}}=0$
$11{\mathrm{V}}_{\mathrm{pp}}-{\mathrm{V}}_0=0$
Closed-loop gain is given by the ratio of output to the input.
so the Closed-loop voltage gain is given by,
$\frac{{\mathrm{V}}_0}{{\mathrm{V}}_{\mathrm{pp}}}=11$