SSE JE Electrical Engineering 10 Dec 2020 Papers

Maximum demand = 200 kW
Load factor = 40%
Tariff rate = Rs. 200 per kW of maximum demand + 10 paise per kWh
Energy consumed per annum (kWh) = (200 × 0.4 × 8760) $=700.80\times {10}^3\mathrm{kWh}$
Annual fixed charge = Rs. 200 per kW of maximum demand
Annual fixed charge = 200 × 200 = Rs 40,000
Running charge = 10 paise per kWh
Running charge $=0.1\times 700.80\times {10}^3$ = Rs 70,800
Total charge or tariff = Rs 40,000 + Rs 70,800 = Rs 1,10,800