SSC MTS Model Paper 8

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Question : 99 of 100

Marks: +1, -0

If a

^{2}

+ b

^{2}

+ c

^{2}

= ab +bc + ac a+C then the value of

(a+c)/b

0
2
1
-1

Solution:

(b) a

^{2}

+ b

^{2}

+ c

^{2}

= ab + bc +ca
= a

^{2}

+ b

^{2}

+ c

^{2}

— ab — bc — ca =0
On m ultiplying by 2,
2a

^{2}

+ 2b

^{2}

+ 2c

^{2}

- 2ab - 2bc -2ca = 0
= a

^{2}

+ b

^{2}

- 2ab + b

^{2}

+ c

^{2}

- 2bc +c

^{2}

+ a

^{2}

- 2ac = 0
= (a - b)

^{2}

+ (b - c)

^{2}

+ (c - a)

^{2}

= 0 =a - b = 0= a =b
b-c=0=b=c
c-a=0=c=a

(a+c)/b

=2a/a=2

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