SSC MTS Model Paper 7

Question : 92 of 99

Marks: +1, -0

A sailor goes 12 km downstream in 48 minutes and returns in 1 hour 20 minutes. The speed of the sailor in still water is :

Solution:

(a) Let the speed of sailor in
still water be x kmph.
and Speed of current = y kmph

x + y = { 12 }/ { { 48 }/ { 60 } } = { 12 }/ { 48 } × 60 = 15

kmph
and,

x - y = { 12 }/ { { 90 }/ { 60 } } = { 12 × 60 }/ { 80 } = 9 { kmph }

Adding these equations,
2x = 15 + 9 = 24
= x = 12 kmph

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