SSC MTS Model Paper 6

Question : 43 of 150

Marks: +1, -0

If ABCD is a rectangle and E, F are the mid-points of BC and AD respectively and G is any point on EF, then ∆GAB equals: 1 1

$1/6$ (rectangle ABCD)
$1/4$ (rectangle ABCD)
$1/3$ (rectangle ABCD)
$1/2$ (rectangle ABCD)

Validate

Solution:

AB || EF || CD. So ABEF is a rectangle

∴ ∆AGB =

1/2

(area of rectangle ABEF)
=

1/2

× (

1/2

area of rectangle ABCD )
=

1/4

(area of rectangle ABCD)
or, If a triangle and a parallelogram are on the same base and between the same parallels then the areaof the triangle is equal to half the area of the parallelogram.

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