SSC MTS Model Paper 5

Question : 45 of 148

Marks: +1, -0

If x

^2

+ y

^2

+ z

^2

+ 2 = 2(y − x), then what will be the value of 3x + 5y + 6z?

Solution:

ATQ,

x ^ { 2 } + 1 + 2 x + y ^ { 2 } + 1 - 2 y + z ^ { 2 } = 0

( x + 1 ) ^ { 2 } + ( y - 1 ) ^ { 2 } + z ^ { 2 } = 0

∴ x = − 1, y = 1, z = 0
Put the above value in equation-
3x + 5y + 6z = 3 × − 1 + 5 × 1 + 6 × 0
= − 3 + 5 = 2

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