SSC MTS Model Paper 5

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Question : 30 of 148

Marks: +1, -0

What will be the minimum value of 4 sin

^{2}

θ + 6 cos

^{2}

θ.

2
4
6
0

Solution:

4 sin

^{2}

θ + 6(1 − sin

^{2}

θ) = 4 sin

^{2}

θ + 6 − 6 sin

^{2}

θ = 6 − 2 sin

^{2}

θ
Now put the value of θ = 90°
∴ 6 − 2 = 4

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