SSC MTS Model Paper 4

Question : 45 of 150

Marks: +1, -0

If the angular diameter of the moon be 30, how far from the eye a coin of diameter 4.4 cm be kept to hide the moon?

Solution:

θ= 30 ^ { ° } = ( { 30 }/ { 60 } ) ^ { ° } = ( { 1 } /{ 2 } \) ^ { ° }

= ( { 1 }/ { 2 } × { π }/ { 180 } ) ^ { { c } } =( { π} /{ 360 } ) ^ { { c } }

θ={ { Arc } } /{ { radius } } = { π }/ { 360 } = { 4.4 } /{ { r } }

⇒ r = { 4.4 × 360 }/ { π } { cm } = { 4.4 × 360 }/ { 22 } × 7

r = 504 cm

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