SSC MTS Model Paper 4

Question : 35 of 150

Marks: +1, -0

A dog is 50 of its own leaps behind a cat. The dog takes 5 leaps per minute to the cat's 4. If the dog and the cat cover 8 m and 5 m per leap respectively, what distance will the dog have to run before it catches the cat?

600 m
700 m
800 m
1000 m

Validate

Solution:

Actual distance b/w cat & dog = 50 × 8 = 400 m
Time taken by dog =

400/20

= 20 min

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