SSC MTS Model Paper 3

Question : 28 of 150

Marks: +1, -0

Ravi and Ajay start simultaneously from the same place A for B, 60 km apart. Ravi's speed is 4 km/hr less than of Ajay. Ajay after reaching at B, returns and meet Ravi at a place 12 km away from B. Ravi's speed is

12 km/hr
10 km/hr
8 km/hr
6 km/hr

Validate

Solution:

Distance travelled by Ravi = (60 − 12) km = 48 km
and distance travelled by Ajay = (60 + 12) km = 72 km
Difference between the distance travelled by them = (72 − 48) km = 24 km
Time required by Ravi =

{ 24 } /{ 4 } { hr } = 6 { hr }

Speed of Ravi =

{ 48 } /{ 6 } { km } / { hr } = 8 { km } / { hr }

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