A is 120% of B and B is 65% of C. If the sum of A, B and C is 121\frac{1}{2}, then the value of 2C – 4B + A is:

SSC MTS 6 Oct 2021 Shift 1 Paper

Question : 68 of 100

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A is 120% of B and B is 65% of C. If the sum of A, B and C is $121\;{1}/{2}$, then the value of 2C – 4B + A is:

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