SSC MTS 6 Aug 2019 Shift 3 Paper

Follow BODMAS rule to solve this question, as per the order is given below:
Step-1: Parts of an equation enclosed in 'Brackets' must be solved first and in the bracket,
Step-2: Any mathematical 'Of' or 'Exponent' must be solved next,
Step-3: Next, the parts of the equation that contain 'Division' and 'Multiplication' are calculated,
Step-4: Last but not least, the parts of the equation that contain 'Addition' and 'Subtraction' should be calculated.
$\frac{3}{4}÷\left(\frac{1}{2}+\frac{1}{16}\right)+\frac{2}{3}\mathrm{of}\frac{4}{9}÷\left(\frac{1}{3}-\frac{11}{81}\right)+\frac{1}{4}\times \frac{2}{3}$
⇒ $\frac{3}{4}÷\left(\frac{9}{16}\right)+\frac{8}{27}÷\left(\frac{16}{81}\right)+\frac{1}{4}\times \frac{2}{3}$
⇒ $\frac{4}{3}+\frac{3}{2}+\frac{2}{12}$
⇒ $\frac{36}{12}$
⇒ 3