SSC MTS 6 Aug 2019 Shift 3 Paper

Tips & Tricks
A = P(1 + r/100)${}^{\mathrm{n}}$
⇒ 3600 = 2400(1 + r/100)${}^6$
⇒ (1 + r/100)${}^6$ = 3/2
For 12 years,
⇒ A = 2400(1 + r/100)${}^{12}$
⇒ A = 2400[(1 + r/100)${}^6$]${}^2$
⇒ A = 2400 × (3/2)${}^2$ = Rs. 5400
∴ The amount after 12 years at the same rate of interest will be Rs. 5400.
Short trick,
The amount after 12 years = (3600 × 3600)/2400 = Rs. 5400