SSC MTS 6 Aug 2019 Shift 2 Paper

The total surface area of a solid hemisphere = $3\mathrm{\pi }{\mathrm{r}}^2$
⇒ The total surface area of a solid hemisphere = 3 × (22/7) × 14${}^2$
⇒ The total surface area of a solid hemisphere = 1848 $\mathrm{c}{\mathrm{m}}^2$
The curved surface area of a solid hemisphere = $2\mathrm{\pi }{\mathrm{r}}^2$
⇒ The curved surface area of a solid hemisphere = 2 × × (22/7) × 14${}^2$
⇒ The curved surface area of a solid hemisphere = 1232 $\mathrm{c}{\mathrm{m}}^2$
∴ The total surface area and curved surface area are 1848 $\mathrm{c}{\mathrm{m}}^2$ and 1232 $\mathrm{c}{\mathrm{m}}^2$.