SSC MTS 6 Aug 2019 Shift 2 Paper

Cost price = CP and Selling price = SP
⇒ CP${}_1$ = 6(Profit)
⇒ CP${}_1$ = 6 × (SP${}_1$ - CP${}_1$)
⇒ 7 × CP${}_1$ = 6 × SP${}_1$
⇒ CP${}_1$ = (6/7) SP${}_1$ ---- (1)
⇒ CP${}_2$ = 3(Loss)
⇒ CP${}_2$ = 3(CP${}_2$ - SP${}_2$ )
⇒ 3 SP${}_2$ = 2 CP${}_2$
⇒ CP${}_2$ = 3/2 SP${}_2$ ---- (2)
If the cost prices of the articles are the same,
From (1) = (2)
⇒ (6/7) SP${}_2$ = 3/2 SP${}_2$
⇒ SP${}_1$/ SP${}_2$ = 7/4
⇒ SP${}_1$ : SP${}_2$ = 7 : 4
∴ The ratio of SP1 and SP2 is 7 : 4.